[
A=
\begin{bmatrix}
1 & 2 & 3
4 & 5 & 6
7 & 8 & 9
\end{bmatrix}
]
Answer:
Element 4 is at position ((2,1)).
Delete row 2 and column 1:
[
\begin{bmatrix}
2 & 3
8 & 9
\end{bmatrix}
]
Minor:
[ M_{21}=(2)(9)-(3)(8) ]
[ =18-24=-6 ]
Cofactor:
[ C_{21}=(-1)^{2+1}(-6) ]
[ =(-1)^3(-6)=6 ]
Final Answer: 6
[
A=
\begin{bmatrix}
2 & 1 & 4
3 & 5 & 6
7 & 8 & 9
\end{bmatrix}
]
Answer:
Element 5 is at position ((2,2)).
Delete row 2 and column 2:
[
\begin{bmatrix}
2 & 4
7 & 9
\end{bmatrix}
]
Minor:
[ M_{22}=(2)(9)-(4)(7) ]
[ =18-28=-10 ]
Cofactor:
[ C_{22}=(-1)^{2+2}(-10) ]
[ =(-10) ]
Final Answer: (-10)
[
A=
\begin{bmatrix}
3 & 1 & 2
4 & 5 & 6
7 & 8 & 9
\end{bmatrix}
]
Answer:
Element 3 is at position ((1,1)).
Delete row 1 and column 1:
[
\begin{bmatrix}
5 & 6
8 & 9
\end{bmatrix}
]
Minor:
[ M_{11}=(5)(9)-(6)(8) ]
[ =45-48=-3 ]
Cofactor:
[ C_{11}=(-1)^{1+1}(-3) ]
[ =-3 ]
Final Answer: (-3)
[
A=
\begin{bmatrix}
1 & 2 & 0
4 & 5 & 6
7 & 8 & 9
\end{bmatrix}
]
Answer:
Element 2 is at position ((1,2)).
Delete row 1 and column 2:
[
\begin{bmatrix}
4 & 6
7 & 9
\end{bmatrix}
]
Minor:
[ M_{12}=(4)(9)-(6)(7) ]
[ =36-42=-6 ]
Cofactor:
[ C_{12}=(-1)^{1+2}(-6) ]
[ =(-1)^3(-6)=6 ]
Final Answer: 6
[
A=
\begin{bmatrix}
1 & 2 & 3
0 & 4 & 5
1 & 0 & 6
\end{bmatrix}
]
Answer:
[
C_{11}=
\begin{vmatrix}
4 & 5
0 & 6
\end{vmatrix}
=24
]
[
C_{12}=-
\begin{vmatrix}
0 & 5
1 & 6
\end{vmatrix}
=-(0-5)=5
]
[
C_{13}=
\begin{vmatrix}
0 & 4
1 & 0
\end{vmatrix}
=(0-4)=-4
]
[
C_{21}=-
\begin{vmatrix}
2 & 3
0 & 6
\end{vmatrix}
=-(12)=-12
]
[
C_{22}=
\begin{vmatrix}
1 & 3
1 & 6
\end{vmatrix}
=6-3=3
]
[
C_{23}=-
\begin{vmatrix}
1 & 2
1 & 0
\end{vmatrix}
=-(0-2)=2
]
[
C_{31}=
\begin{vmatrix}
2 & 3
4 & 5
\end{vmatrix}
=10-12=-2
]
[
C_{32}=-
\begin{vmatrix}
1 & 3
0 & 5
\end{vmatrix}
=-(5)=-5
]
[
C_{33}=
\begin{vmatrix}
1 & 2
0 & 4
\end{vmatrix}
=4
]
Cofactor Matrix:
[
\begin{bmatrix}
24 & 5 & -4
-12 & 3 & 2
-2 & -5 & 4
\end{bmatrix}
]
Answer:
[ C_{ij}=(-1)^{i+j}M_{ij} ]
where:
[
A=
\begin{bmatrix}
2 & 1 & 3
4 & 5 & 6
7 & 8 & 1
\end{bmatrix}
]
Answer:
Element 7 is at position ((3,1)).
Delete row 3 and column 1:
[
\begin{bmatrix}
1 & 3
5 & 6
\end{bmatrix}
]
Minor:
[ M_{31}=(1)(6)-(3)(5) ]
[ =6-15=-9 ]
Cofactor:
[ C_{31}=(-1)^{3+1}(-9) ]
[ =(-9) ]
Final Answer: (-9)
[
A=
\begin{bmatrix}
1 & 2 & 3
4 & 5 & 6
0 & 1 & 2
\end{bmatrix}
]
Answer:
Element 6 is at position ((2,3)).
Delete row 2 and column 3:
[
\begin{bmatrix}
1 & 2
0 & 1
\end{bmatrix}
]
Minor:
[ M_{23}=(1)(1)-(2)(0)=1 ]
Cofactor:
[ C_{23}=(-1)^{2+3}(1) ]
[ =-1 ]
Final Answer: (-1)
Answer:
A cofactor matrix is the matrix formed by replacing every element of a matrix with its corresponding cofactor.
Answer:
The adjoint (adjugate) of a matrix is obtained by taking the transpose of the cofactor matrix.
[ \text{Adj}(A)=(\text{Cofactor Matrix})^T ]